Answer to Question #291589 in Statistics and Probability for Kang

Question

Two balls are drawn in succession without replacement from an urn containing 9 yellow balls and 6 green balls. Let X

X be the random variable representing the number of yellow balls.

Question: How many possible outcomes are there in this experiment?

Answer 1

The possible outcomes are,

(1)Both yellow balls

(2)green ball in the first draw and yellow ball in the second draw

(3)yellow ball in the first draw and green ball in the second draw

(4) green balls in both the draws.

For possibility

(1), possible outcomes are 9 x 8=72

(2) possible outcomes are 6 x 9=54

(3) possible outcomes are 9 x 6=54

(4)possible outcomes are 6 x 5=30

The total number of outcomes is

72+54+54+30= 210