Determine the area under the standard normal distribution curve between z=1.15 and z=-1.85
P(−1.85<Z<1.15)=P(Z<1.15)–P(Z<−1.85)=0.8748−0.0322=0.8427P(-1.85<Z<1.15) = P(Z<1.15) –P(Z<-1.85)\\ =0.8748-0.0322=0.8427\\P(−1.85<Z<1.15)=P(Z<1.15)–P(Z<−1.85)=0.8748−0.0322=0.8427
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