Question #290685

Let X be a discrete random variable such that X = 0 with probability 0.5 and X = 1 with probability 0.5. Let Y be a discrete random variable such that Y = 0 when X = 1 and Y = 1 when X = 0. What is the mean and variance of X + Y?


1
Expert's answer
2022-01-26T09:50:54-0500

If X=0,X=0, then X+Y=0+1=1.X+Y=0+1=1.

If X=1,X=1, then X+Y=1+0=1.X+Y=1+0=1.

Then P(X+Y=1)=1.P(X+Y=1)=1.


mean=E(X+Y)=1mean=E(X+Y)=1

Var(X+Y)=E((X+Y)2)(E(X+Y))2=0Var(X+Y)=E((X+Y)^2)-(E(X+Y))^2=0

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