Answer to Question #290422 in Statistics and Probability for lusientoo

Question

The weights of 1,000 children, in average, is 55kg with standard deviation of 17kg. Suppose the weights are normally distributed, how many children weigh greater than 38kg?

Answer 1

Use Z calculations

Z(38) = (38 - 55)/17 = -1

The area to the right of the Z score is obtained as below;

( 1 - 0.15866) = 0.84134

The number of children weighing greater than 38 kg is given as;

( 0.84134 * 1000) = 841.34

Which is approximately 842 children.