Question #290419

The weights of 1,000 children, in average, is 50kg with standard deviation of 14kg. Suppose the weights are normally distributed, how many children weigh between 53kg and 68kg?


Expert's answer

Let X be a random variable represents the weight of randomly selected child, then X~N(50,142)N(50,14^2)

P(53<X<68)=P(53<N(50,142)<68)=P(53<50+14N(0,1)<68)=P(0.214<N(0,1)<1.071)=P(N(0,1)<1.071)P(N(0,1)<0.214)=0.857920.58473=0.27319P(53<X<68)=P(53<N(50,14^2)<68)=P(53<50+14N(0,1)<68)=P(0.214<N(0,1)<1.071)=P(N(0,1)<1.071)-P(N(0,1)<0.214)=0.85792-0.58473=0.27319

So, approximately 1000*0.27319=273.19=(round to integer)=273 children have such a weight.


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