Question

Suppose two dice was rolled. Let Y be the random variable representing the number of even number that occur. Find the values of the random variable Y.

Answer 1

$P(Y=0)=\frac{9}{36}=\frac{1}{4}.$

$P(Y=1)=\frac{18}{36}=\frac{1}{2}.$

$P(Y=2)=\frac{9}{36}=\frac{1}{4}.$