Question #289744

) In a study of TV viewing habits, it is desired to estimate the average number of hours that learners spend




watching per week. If it is reasonable to assume that




  3.2




hours, how large a sample is needed so that it




will be possible to assert with 95% confidence that the sample mean is off by less than 20 minutes? �

1
Expert's answer
2022-01-25T11:15:16-0500

Given σ=4.8hoursXμ<1.96×4.8n1.96×4.8n>139.408n>131n>128.224n=28.2242n=796.59Given~\sigma=4.8hours\\ |X-\mu|<1.96\times\frac{4.8}{\sqrt{n}}\\ 1.96\times\frac{4.8}{\sqrt{n}}>\frac{1}{3}\\ \frac{9.408}{\sqrt{n}}>\frac{1}{3}\\ \frac{1}{\sqrt{n}}>\frac{1}{28.224}\\ n=28.224^2\\ n=796.59


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