Question #289640

The probabilities that a printer produces 0,1,2 and 3 misprints are 42% , 28%, 18% and 12% respectively. What is the mean value of the variable?



1
Expert's answer
2022-01-24T17:07:41-0500

μ=0∗0.42+1∗0.28+2∗0.18+3∗0.12=1.\mu=0*0.42+1*0.28+2*0.18+3*0.12=1.


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