Question #289410

A discrete random variable x has an expected value of 45 and variance of 16. Let us say we double every x's within the probability distribution. What will be the new variance?

Expert's answer

Var(x)=16Var(2x)=22var(x)=4×16=64Var(x)=16\\Var(2x)=2^2var(x)\\ =4\times 16=64


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