Question #289015

A box contains 5 balls. One is numbered 1, two are numbered 2, and two are numbered 3. The balls are mixed and one is selected at random. After a ball is selected, its number is recorded. Then it is replaced. If the experiment is repeated many times, find the standard deviation of the numbers on the balls.


1
Expert's answer
2022-01-20T13:50:40-0500

mean=E(x)=xp(x)E(x)=1×15+2×25+3×25E(x)=2.2variance=E(x2)(E(x))2E(x2)=12×15+22×25+32×25E(x2)=5.4(E(x))2=(2.2)2=4.84variance=E(x2)(E(x))25.44.84=0.56S.D=0.56=0.7483mean=E(x)=\sum xp(x)\\ E(x)=1\times\frac{1}{5}+2\times\frac{2}{5}+3\times\frac{2}{5}\\E(x)=2.2\\ variance=E(x^2)-(E(x))^2\\E(x^2)=1^2\times\frac{1}{5}+2^2\times\frac{2}{5}+3^2\times\frac{2}{5}\\ E(x^2)=5.4\\(E(x))^2=(2.2)^2=4.84\\variance=E(x^2)-(E(x))^2\\5.4-4.84=0.56\\ S.D=\sqrt{0.56}=0.7483


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