Question #289015

A box contains 5 balls. One is numbered 1, two are numbered 2, and two are numbered 3. The balls are mixed and one is selected at random. After a ball is selected, its number is recorded. Then it is replaced. If the experiment is repeated many times, find the standard deviation of the numbers on the balls.


Expert's answer

mean=E(x)=xp(x)E(x)=1×15+2×25+3×25E(x)=2.2variance=E(x2)(E(x))2E(x2)=12×15+22×25+32×25E(x2)=5.4(E(x))2=(2.2)2=4.84variance=E(x2)(E(x))25.44.84=0.56S.D=0.56=0.7483mean=E(x)=\sum xp(x)\\ E(x)=1\times\frac{1}{5}+2\times\frac{2}{5}+3\times\frac{2}{5}\\E(x)=2.2\\ variance=E(x^2)-(E(x))^2\\E(x^2)=1^2\times\frac{1}{5}+2^2\times\frac{2}{5}+3^2\times\frac{2}{5}\\ E(x^2)=5.4\\(E(x))^2=(2.2)^2=4.84\\variance=E(x^2)-(E(x))^2\\5.4-4.84=0.56\\ S.D=\sqrt{0.56}=0.7483


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