Given that X and Y are independent random variables and E(X) = 4, E(Y) = 7, Var(X) = 3, Var(Y) = 6; find Var(5X - 6).
Given, E(X) = 4, E(Y) = 7, Var(X) = 3, Var(Y) = 6
"Var(5X - 6)=25Var(X)" "[\\because Var[aX + b] = a^2Var(X)]"
"\\Rightarrow Var(5X - 6)=25\\times 3=75"
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