Given that X and Y are independent random variables and E(X) = 4, E(Y) = 7, Var(X) = 3, Var(Y) = 6; find Var(5X - 6).
Given, E(X) = 4, E(Y) = 7, Var(X) = 3, Var(Y) = 6
Var(5X−6)=25Var(X)Var(5X - 6)=25Var(X)Var(5X−6)=25Var(X) [∵Var[aX+b]=a2Var(X)][\because Var[aX + b] = a^2Var(X)][∵Var[aX+b]=a2Var(X)]
⇒Var(5X−6)=25×3=75\Rightarrow Var(5X - 6)=25\times 3=75⇒Var(5X−6)=25×3=75
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