Determine whether it can serve as the probability distribution of a random variable X. Explain your answer.
P(X)= 3+x / 3-x for X= 1, 2, 3, 4
We are given that,
"P(X)= (3+x) \/ (3-x) \\space for \\space x= 1, 2, 3, 4"
Now,
"P(1)={(3+1)\\over(3-1)}={4\\over2}=2\\\\\nP(2)={(3+2)\\over(3-2)}={5\\over1}=5\\\\\nP(3)={(3+3)\\over(3-3)}={6\\over0}=\\infin\\\\\nP(4)={(3+4)\\over(3-4)}={7\\over-1}=-7\\\\"
For "P(x)" to be a probability distribution then it must satisfy the condition that "\\sum P(X)=1"
So,
"\\sum P(X)=2+5+\\infin+-7=\\infin"
Clearly, "P(X)" cannot serve as a probability distribution because, "\\displaystyle\\sum_{\\forall x} P(X)\\not=1"
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