Question #28686

When a missile is fired from a ship, the probability that it is intercepted is 1/3. The probability that the missile hits the target, given that it is not intercepted is 3/4. If three missiles are fired independently from the ship, the probability that all three hits the target, is what?

Expert's answer

When a missile is fired from a ship, the probability that it is intercepted is 1/3. The probability that the missile hits the target, given that it is not intercepted is 3/4. If three missiles are fired independently from the ship, the probability that all three hits the target, is what?

Probability that missile isn't intercepted equals:


P(ni)=1P(i)P(n i) = 1 - P(i)

P(i)P(i) - probability that missile is intercepted


P(ni)=113=23P(n i) = 1 - \frac{1}{3} = \frac{2}{3}


Probability that missile isn't intercepted AND missile hits the target equals:


P1=P(ni)P(h)P_1 = P(n i) * P(h)

P(h)P(h) - probability the missile hits the target, given that it is not intercepted


P1=2334=12P_1 = \frac{2}{3} \cdot \frac{3}{4} = \frac{1}{2}


If three missiles are fired independently from the ship, the probability that all three hits the target equals:


P3=P13=(12)3=18P_3 = P_1^3 = \left(\frac{1}{2}\right)^3 = \frac{1}{8}


Answer: probability that all three hits the target equals 18\frac{1}{8}

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