Answer to Question #286541 in Statistics and Probability for RobertsJulia

Question

Find the mean of the probability distribution

of random variable X, which can take only the

values

3, 5. and 7, given that P(3)=7/30, P(5)=10/30

and P(7)=13/30.

Answer 1

$M(X) = \sum {{x_i}} {p_i} = 3 \cdot \frac{7}{{30}} + 5 \cdot \frac{{10}}{{30}} + 7 \cdot \frac{{13}}{{30}} = \frac{{27}}{5}$

Answer: $\frac{{27}}{5}$