Question #28571

20. A new car salesperson knows that she sells a car to one customer out of 20 who enter the showroom.
Find the probability that she'll sell a car to exactly two of the next three customers.
A. 0.9939
B. 0.0075
C. 0.0071
D. 0.1354

Expert's answer

A new car salesperson knows that she sells a car to one customer out of 20 who enter the showroom.

Find the probability that she'll sell a car to exactly two of the next three customers.

A. 0.9939

B. 0.0075

C. 0.0071

D. 0.1354

Solution.

1. Let AA be the event of selling a car to a customer. Then, according to the conditions P(A)=1/20=0.05P(A) = 1 / 20 = 0.05 and P(A)=1P(A)=0.95P(\overline{A}) = 1 - P(A) = 0.95.

2. Let BB be the event of selling a car to two customers out of the next three ones. Then


B=AˉAA+AAˉA+AAAˉ.B = \bar{A} A A + A \bar{A} A + A A \bar{A}.


As the events AˉAA,AAˉA,AAAˉ\bar{A} A A, A \bar{A} A, A A \bar{A} are incompatible then


P(B)=P(AˉAA)+P(AAˉA)+P(AAAˉ)P(B) = P(\bar{A} A A) + P(A \bar{A} A) + P(A A \bar{A})


and


P(B)=3P(AˉAA)=3P(Aˉ)P(A)P(A)=30.950.050.05=0.007125.P(B) = 3 P(\bar{A} A A) = 3 P(\bar{A}) P(A) P(A) = 3 * 0.95 * 0.05 * 0.05 = 0.007125.


Answer: 0.007125.

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