Question #285314

A shopping mall has setup a promotion as follows .with any mall purchase of 50 or more the customer gets to spin the wheel shown here.if a number 1 comes up the customer wins 10 .if the number 2 comes up the customer wins 5 and If the number 3 or 4 comes up the customer wins a discount coupon .find the customer wins 10




1
Expert's answer
2022-01-07T13:36:30-0500


From the given wheel picture, the probability distribution of numbers is as follows:


Win Money$10$5Discount CouponX(Number)123             4P(X)2/202/208/20       8/20\def\arraystretch{1.5} \begin{array}{c:c:c:c} Win\ Money & \$10 & \$5 & Discount \ Coupon \\ \hline X(Number) & 1 & 2 & 3 \ \ \ \ \ \ \ \ \ \ \ \ \ 4 \\ \hdashline P(X) & 2/20 & 2/20 & 8/20 \ \ \ \ \ \ \ 8/20 \end{array}

Probability that the customer win $10 is 2/20=0.1.2/20=0.1.

 


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