Question #28530

south african captain lost th etoss of a coin 13 times out of 14 . the chance of this happening is?

Expert's answer

Task. South african captain lost the toss of a coin 13 times out of 14. Find the chance of this happening is?

Proof. Let XX be the random variable equal to the number of wins the toss of a coin out of 14 tosses. Assuming that the chances to loss and to win are equal, so their probabilities are equal to 0.5, we obtain that XX ras binomial distribution with n=14n=14 p=0.5p=0.5, and q=1p0.5q=1-p-0.5. Hence the chance to lost kk times out of nn is equal to

P(X=k)=Cnkpnkqk,P(X=k)=C_{n}^{k}p^{n-k}q^{k},

where

Cnk=n!k!(nk)!C_{n}^{k}=\frac{n!}{k!(n-k)!}

is the binominal coefficient, and k!=k(k1)21k!=k(k-1)\cdots 2\cdot 1.

For k=13k=13 we obtain that

P(X=13)=C14130.510.513=14!13!1!0.514=141321132110.514=140.5140.00085449.P(X=13)=C_{14}^{13}\cdot 0.5^{1}\cdot 0.5^{13}=\frac{14!}{13!\cdot 1!}\cdot 0.5^{14}=\frac{14\cdot 13\cdots 2\cdot 1}{13\cdots 2\cdot 1\cdot 1}\cdot 0.5^{14}=14\cdot 0.5^{14}\approx 0.00085449.

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