Question #284985

find the range variance and standard deviation of 2.1,3.0,1.9,1.5,4.8

1
Expert's answer
2022-01-10T16:42:46-0500

Sorted Data Set: 1.5,1.9,2.1,3.0,4.81.5, 1.9, 2.1, 3.0, 4.8


Range=4.81.5=3.3Range=4.8-1.5=3.3

mean=μ=15(1.5+1.9+2.1+3.0+4.8)mean=\mu=\dfrac{1}{5}(1.5+1.9+2.1+3.0+4.8)

=2.66=2.66

Var(x)=σ2=15((1.52.66)2+(1.92.66)2Var(x)=\sigma^2=\dfrac{1}{5}((1.5-2.66)^2+(1.9-2.66)^2

+(2.12.66)2+(3.02.66)2+(4.82.66)2)+(2.1-2.66)^2+(3.0-2.66)^2+(4.8-2.66)^2)

=1.3864=1.3864

σ=σ2=1.38641.177455\sigma=\sqrt{\sigma^2}=\sqrt{1.3864 }\approx1.177455


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