Question #284594

Suppose speeds of vehicles on a particular stretch of roadway are normally distributed with mean 36.6 mph and standard deviation 1.7 mph. Find the probability that the mean speed of 20 randomly selected vehicles is between 35 and 40 mph


Expert's answer

Let X=X= the mean speed of 20 randomly selected vehicles: XN(μ,σ2/n).X\sim N(\mu, \sigma^2/n).

Given μ=36.6mph,σ=1.7mph,n=20\mu=36.6mph, \sigma=1.7mph, n=20


P(35<X<40)=P(X<40)P(X35)P(35<X<40)=P(X<40)-P(X\leq 35)

=P(Z<40μσ/n)P(Z35μσ/n)=P(Z<\dfrac{40-\mu}{\sigma/\sqrt{n}})-P(Z\leq \dfrac{35-\mu}{\sigma/\sqrt{n}})

=P(Z<4036.61.7/20)P(Z3536.61.7/20)=P(Z<\dfrac{40-36.6}{1.7/\sqrt{20}})-P(Z\leq \dfrac{35-36.6}{1.7/\sqrt{20}})

P(Z<8.944272)P(Z4.209069)\approx P(Z<8.944272)-P(Z\leq -4.209069)

10.0000130.999987\approx1-0.000013\approx0.999987

The probability that the mean speed of 20 randomly selected vehicles is between 35 and 40 mph is 0.999987.0.999987.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

LATEST TUTORIALS
APPROVED BY CLIENTS