Question #283931

A production facility contains two machines that are used to rework items that are initially defective. Let ๐‘‹ be the number of hours that the first machine is in use and let ๐‘Œ be the number of hours that the second machine is in use, on a randomly chosen day. Assume that ๐‘‹ and ๐‘Œ have a joint probability density function given by ๐‘“(๐‘ฅ) = { 3 2 (๐‘ฅ 2 + ๐‘ฆ 2 ) 0 < ๐‘ฅ < 1 ๐‘Ž๐‘›๐‘‘ 0 < ๐‘ฆ < 1 0 ๐‘œ๐‘กโ„Ž๐‘’๐‘Ÿ๐‘ค๐‘–๐‘ ๐‘’. a. What is the probability that both machines are in operation for less than half an hour?


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Expert's answer
2022-01-11T14:32:04-0500

P(0<x<0.5,0<y<0.5)=โˆซ00.5โˆซ00.5f(x)dxdy=P(0<x<0.5,0<y<0.5)=\int^{0.5}_0\int^{0.5}_0 f(x)dxdy=


=โˆซ00.5โˆซ00.532(x2+y2)dxdy=32โˆซ00.5(x3/3+xy2)00.5dy==\int^{0.5}_0\int^{0.5}_0 \frac{3}{2}(x^2+y^2)dxdy=\frac{3}{2}\int^{0.5}_0(x^3/3+xy^2)^{0.5}_0dy=


=32โˆซ00.5(1/24+y2/2)dy=32(y/24+y3/6)โˆฃ00.5==\frac{3}{2}\int^{0.5}_0(1/24+y^2/2)dy=\frac{3}{2}(y/24+y^3/6)|^{0.5}_0=


=32(1/48+1/48)=1/16=\frac{3}{2}(1/48+1/48)=1/16


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