Answer to Question #283674 in Statistics and Probability for Nery

Question

Suppose the average number of calls received by an operator in one minute is 2. What is the probability of receiving 10 calls in 5 minutes ?

Answer 1

This is a Poisson distribution with the mean of $2*5=10.$

$P(X=10)=e^{-10}\frac{10^{10}}{10!}=0.1251.$