Question #283552

The following data shows frequency distribution of error page of a book. Fit Poisson distribution to the following :


Number error - 1,2,3,4,5,6,7,8


Frequency-12,18,19,05,09,14,12,11

1
Expert's answer
2021-12-30T05:57:48-0500
xifixifiP(X=xi)Expectedvalue112120.0601616218360.12814313319570.1819631845200.1937911959450.16511017614840.11722812712840.0713417811880.037989490.0442744\def\arraystretch{1.5} \begin{array}{c:c:c:c:c} x_i & f_i & x_if_i & P(X=x_i) & Expected\\ & & & & value\\ \hline 1 & 12 & 12 & 0.060161 & 6 \\ \hdashline 2 & 18 & 36 & 0.128143 & 13 \\ \hdashline 3 & 19 & 57 & 0.181963 & 18 \\ \hdashline 4 & 5 & 20 & 0.193791 & 19 \\ \hdashline 5 & 9 & 45 & 0.165110 & 17\\ \hdashline 6 & 14 & 84 & 0.117228 & 12 \\ \hdashline 7 & 12 & 84 & 0.071341 & 7 \\ \hdashline 8 & 11 & 88 & 0.037989 & 4 \\ \hdashline 9 & & & 0.044274 & 4 \\ \hdashline \end{array}

mean=μ=ixifiifi=426100=4.26mean=\mu=\dfrac{\sum_ix_i f_i}{\sum_if_i}=\dfrac{426}{100}=4.26

λ=μ=4.26\lambda=\mu=4.26

P(X=xi)=eλλxi(xi)!P(X=x_i)=\dfrac{e^{-\lambda}\cdot\lambda^{x_i}}{(x_i)!}


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