Question #283262

Construct the discrete series. Count unbiased estimates of the general mean and general variance. Find the confidence interval for expectation with a confidence level of 0.05 5, 11, 13, 9, 11, 5, 7, 7, 5, 9, 13, 13, 11, 9, 5, 9, 11, 9, 5, 9, 11, 9, 9, 5


1
Expert's answer
2021-12-29T10:47:21-0500

Data set: (5, 11, 13, 9, 11, 5, 7, 7, 5, 9, 13, 13, 11, 9, 5, 9, 11, 9, 5, 9, 11, 9, 9, 5)


Mean=ΣXn=5+11+13+9+11+5+7+7+5+9+13+13+11+9+5+9+11+9+5+9+11+9+9+524=8.75Mean=\frac{\Sigma X}{n}=\frac{5+11+13+9+11+5+7+7+5+9+13+13+11+9+5+9+11+9+5+9+11+9+9+5}{24}=8.75

Following table shows the calculation of standard deviation:


s=Σ(XXˉ)2n1=170.50241=2.72s=\sqrt{\frac{\Sigma(X-\bar{X})^2}{n-1}}=\sqrt{\frac{170.50}{24-1}}=2.72


Formula for the 95% confidence interval is:

CI=Xˉ±ZsnCI=\bar{X}\pm Z\frac{s}{\sqrt{n}}


CI=8.75±1.96×2.7224CI=8.75\pm 1.96\times\frac{2.72}{\sqrt{24}}


CI=8.75±1.09CI=8.75\pm 1.09


CI=(7.66,9.84)CI=(7.66, 9.84)



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