Question #282331

assume that the population consists of 7 containers having the following weight 6,7,8,9,10,11,12. Find mean μ and standard deviation.


1
Expert's answer
2021-12-24T08:57:27-0500
mean=μ=6+7+8+9+10+11+127=9mean=\mu=\dfrac{6+7+8+9+10+11+12}{7}=9

σ2=17((69)2+(79)2+(89)2\sigma^2=\dfrac{1}{7}((6-9)^2+(7-9)^2+(8-9)^2

+(99)2+(109)2+(119)2+(129)2)+(9-9)^2+(10-9)^2+(11-9)^2+(12-9)^2)

=4=4

σ=σ2=4=2\sigma=\sqrt{\sigma^2}=\sqrt{4}=2

Mean μ=9,\mu=9, standard deviation σ=2.\sigma=2.


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