Find the coefficient of quartile deviation from the following:
Class 5 – 10 10 – 15 15 – 20 20 – 25 25 – 30 30 – 35 35 – 40
Frequency 6 8 17 21 15 11 2
9. Find the semi-inter-quartile range for the following data:
Marks 0 – 10 10 – 20 20 – 30 30 – 40 40 – 50
No. of students 22 38 46 35 19
10. Find which of the following industry has less variation if the salaries paid to the employees
are as given below:
Salary (Rs. in
1000’s)
Below
4500
4500 –
4700
4700 –
4900
47900 –
5100
5100 &
above
Industry A 6 13 20 7 6
Industry B 4 9 16 7 0
8.
"n=80"
Q1 class :
Class with (n/4)th value of the observation in cf (cumulative frequency) column
=(80/4)th value of the observation in cf column
=(20)th value of the observation in cf column
and it lies in the class 15-20.
∴Q1 class : 15-20
The lower boundary point of 15-20 is 15.
∴L=15
"Q_1=L+\\frac{n\/4-cf}{f}c=15+\\frac{20-14}{17}\\cdot5=16.76"
Q3 class :
Class with (3n/4)th value of the observation in cf (cumulative frequency) column
=(3"\\cdot" 80/4)th value of the observation in cf column
=(60)th value of the observation in cf column
and it lies in the class 25-30.
∴Q3 class : 25-30
The lower boundary point of 25-30 is 25.
∴L=25
"Q_3=L+\\frac{3n\/4-cf}{f}c=25+\\frac{60-52}{15}\\cdot5=27.67"
Coefficient of Quartile deviation:
"\\frac{Q_3-Q_1}{Q_3+Q_1}=\\frac{27.67-16.76}{27.67+16.76}=0.245"
9.
"n=160"
Q1 class :
Class with (n/4)th value of the observation in cf (cumulative frequency) column
=(160/4)th value of the observation in cf column
=(40)th value of the observation in cf column
and it lies in the class 10-20.
∴Q1 class : 10-20
The lower boundary point of 10-20 is 10.
∴L=10
"Q_1=L+\\frac{n\/4-cf}{f}c=10+\\frac{40-22}{38}\\cdot10=14.74"
Q3 class :
Class with (3n/4)th value of the observation in cf (cumulative frequency) column
=(3"\\cdot" 160/4)th value of the observation in cf column
=(120)th value of the observation in cf column
and it lies in the class 25-30.
∴Q3 class : 30-40
The lower boundary point of 30-40 is 30.
∴L=30
"Q_3=L+\\frac{3n\/4-cf}{f}c=30+\\frac{120-106}{35}\\cdot10=34"
semi-inter-quartile range:
"\\frac{Q_3-Q_1}{2}=\\frac{34-14.74}{2}=9.63"
10.
for A:
Mean:
"\\mu=\\frac{\\sum f_ix_i}{n}=4776.92"
Standard deviation:
"\\sigma=\\sqrt{\\frac{\\sum f_ix_i^2-(\\sum f_ix_i)^2\/n}{n}}=227.54"
Coefficient of Variation:
"k=\\sigma\/\\mu=227.54\/4776.92=4.76\\%"
for B:
Mean:
"\\mu=\\frac{\\sum f_ix_i}{n}=4744.44"
Standard deviation:
"\\sigma=\\sqrt{\\frac{\\sum f_ix_i^2-(\\sum f_ix_i)^2\/n}{n}}=180.19"
Coefficient of Variation:
"k=\\sigma\/\\mu=180.19\/4744.44=3.8\\%"
so, industry B has less variation
Comments
Leave a comment