Two digits are selected at random from the digits 1 through 9
If the sum is even, find the probability that both the numbers are odd.
Solution:
Let A=Getting two odd numbers
B=Getting the sum as an even number.
Required probability:
"P(A|B)=\\frac{P(A\\cap B)}{P(B)}=\\frac{C^2_5\/C^2_9}{(C^2_4+C^2_4)\/C^2_9}=\\frac{C^2_5}{C^2_4+C^2_5}=10\/16=5\/8"
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