Question #280261

Scientific and analysis report from Humanization and Social Journal shows the mean of marriage age in Asia region IS at 25.2 years. A random of sampling is taken and as the new result, the of ages of 35 couples had a mean of 28.7 years and a standard deviation of 4.6


years. According to this new sampling, test at the 0.05 level of significance if the mean age of married couples is different from 25.2 years.



Expert's answer

We test the following hypotheses;

H0:μ=25.2 vs H1:μ25.2H_0:\mu=25.2\space vs \space H_1: \mu\not=25.2

n=35, xˉ=28.7, s=4.6, α=0.05n=35, \space \bar{x}=28.7,\space s=4.6,\space \alpha=0.05

The test statistic is given by,

t=(xˉμ)(sn)=(28.725.2)(4.635)=4.50t={(\bar{x}-\mu)\over ({s\over\sqrt{n}})}={(28.7-25.2)\over({4.6\over\sqrt{35}})}=4.50

tt is compared with the student's t distribution table value at α=0.05\alpha=0.05 with n1=351=34n-1=35-1=34 degrees of freedom given as,

t0.052,34=t0.025,34=2.032245t_{{0.05\over2},34}=t_{0.025,34}= 2.032245

The null hypothesis is rejected if, t>t0.025,34|t|\gt t_{0.025,34}

Since t=4.50>t0.025,34=2.032245,|t|=4.50\gt t_{0.025,34}=2.032245, we reject the null hypothesis and conclude that there is sufficient evidence to show that the mean age of married couples is different from 25.2 years at 5% significance level.


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