An event has 50 female contestants and 13 male contestants. A random sample of 12 contestants is drawn. What is the probability that exactly 8 of the contestant will be female?
p(female) =5050+13=0.79= \frac{50}{50+13} = 0.79=50+1350=0.79
n=12
x=8
Binomial distribution
P(X=x)=Cx12(0.79)x(1−0.79)12−xP(X=8)=C812(0.79)8(1−0.79)12−8=495×0.798×0.214=495×0.15171×0.001944=0.14598P(X=x) = C^{12}_x(0.79)^x(1-0.79)^{12-x} \\ P(X=8) = C^{12}_8(0.79)^8(1-0.79)^{12-8} \\ = 495 \times 0.79^8 \times 0.21^4 \\ = 495 \times 0.15171 \times 0.001944 \\ = 0.14598P(X=x)=Cx12(0.79)x(1−0.79)12−xP(X=8)=C812(0.79)8(1−0.79)12−8=495×0.798×0.214=495×0.15171×0.001944=0.14598
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