What is the variance of the following given sample of daily travel expenses of audit staff: 130, 50, 90, 80, 70, 125, 180, 80, 110?
Mean μ=130+50+90+80+70+125+180+80+1109=9059=100.56.\mu=\frac{130+50+90+80+70+125+180+80+110}{9}=\frac{905}{9}=100.56.μ=9130+50+90+80+70+125+180+80+110=9905=100.56.
Sample variance:
σ2=19−1[(130−100.56)2+(50−100.56)2+(90−100.56)2+(80−100.56)2+(70−100.56)2+(125−100.56)2+(180−100.56)2+(80−100.56)2+(110−100.56)2]=1627.78.\sigma^2=\frac{1}{9-1}[(130-100.56)^2+(50-100.56)^2+(90-100.56)^2+(80-100.56)^2+(70-100.56)^2+(125-100.56)^2+(180-100.56)^2+(80-100.56)^2+(110-100.56)^2]=1627.78.σ2=9−11[(130−100.56)2+(50−100.56)2+(90−100.56)2+(80−100.56)2+(70−100.56)2+(125−100.56)2+(180−100.56)2+(80−100.56)2+(110−100.56)2]=1627.78.
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