Question

a bag 10 white, 15 red and 8 green balls. A single draw of 3 balls is made. what is the probability that a white, a red and green balls are drawn

Answer 1

$P = \frac{C^{10}_1 \times C^{15}_1 \times C^8_1}{C^{33}_1} \\ = \frac{10 \times 15 \times 8}{5456} \\ = 0.2199$