Question #277829

 1.    The net amount of jam in a standard jar produced by a certain food manufacturer has a normal distribution with mean 340 grams and standard deviation 5 grams.

a.    A jar of jam is rejected if its amount differs from the mean by more than 6 grams.

 

What is the probability that a randomly selected jar of jam will be rejected?

 

[4 marks]

 

b.    Estimate the number of rejected jars if a wholesaler has ordered 500 jars of jam from the manufacturer.

 

c.     Estimate the number of accepted jars if a wholesaler has ordered 300 jars of jam from the manufacturer.


1
Expert's answer
2021-12-12T17:24:29-0500

a.

z=xμσ=±65=±1.2z=\frac{x-\mu}{\sigma}=\pm\frac{6}{5}=\pm 1.2


probability that a randomly selected jar of jam will be rejected:

P(z<1.2)+P(z>1.2)=20.1151=0.2302P(z<-1.2)+P(z>1.2)=2\cdot0.1151=0.2302


b.

number of rejected jars:

5000.2302=115.1115500\cdot0.2302=115.1\approx115


c.

number of accepted jars:

300(10.2302)=230.94231300(1-0.2302)=230.94\approx231


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