Question

In a shipment of 10 laptops, 3 are defective. If 3 laptops from this shipment are randomly selected and not replaced, what is the probability that all 3 are defective? Record your answer as a fraction in simplest form.

Answer 1

$$\dfrac{3}{10}(\dfrac{2}{9})(\dfrac{1}{8})=\dfrac{1}{120}$$