Question #277409

1.5, 2.5, 2.5, 4.1, 5, 6.7, 8.12, 9.9, 10.5, 10.4



Determine the mean and standard deviation

1
Expert's answer
2021-12-09T13:44:09-0500

n= 10

μ=n\mu=\frac{\sum}{n}

μ=1.5+2.5+.....+10.410\mu=\frac{1.5+2.5+.....+10.4}{10}


μ=6.122\mu =6.122

Std dev

in(xixˉ2)n1\sqrt{\sum_i^n\frac{(x_i-\bar x^2)}{n-1}}

(1.56.122)2+.....(10.46.122)2)9\sqrt{\sum\frac{(1.5-6.122)^2+.....(10.4-6.122)^2)}{9}}

=3.4804


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