Question #276618

The number of men and women among professors in Math, Physics, Chemistry, Linguistics, and English departments from a SRS of small colleges were counted, and the results are shown in the table below.

Dept. Math. Physics. Chemistry. Linguistics English

Men 58 74 36 12 25

Women. 5 7 10 11 20

Test the claim that the gender of a professor is independent of the department. Use the significance level 𝛼=0.01

(a) The test statistic is 𝜒2 =

 

(b) The critical value is 𝜒2 =



1
Expert's answer
2021-12-08T08:53:42-0500

The hypotheses tested are,

H0:H_0: Gender of a professor is independent of the department.

AgainstAgainst

H1:H_1: gender of a professor is not independent of the department.

We first determine the expected count for each cell using the formula below,

Eij=(ricj)/n, i=1,2 & j=1,2,3,4,5E_{ij}=(r_i*c_j)/n, \space i=1,2\space \& \space j=1,2,3,4,5, where rir_i is the corresponding row total for each cell and cjc_j is the corresponding column total for each cell. n=258n=258 is the sample size.


The expected counts are as follows,

E11=(r1c1)/n=(63205)/258=50.06E_{11}=(r_1*c_1)/n=(63*205)/258=50.06

E12=(r1c2)/n=(81205)/258=64.36E_{12}=(r_1*c_2)/n=(81*205)/258=64.36

E13=(r1c3)/n=(46205)/258=36.55E_{13}=(r_1*c_3)/n=(46*205)/258=36.55

E14=(r1c4)/n=(23205)/258=18.28E_{14}=(r_1*c_4)/n=(23*205)/258=18.28

E15=(r1c5)/n=(45205)/258=35.76E_{15}=(r_1*c_5)/n=(45*205)/258=35.76

E21=(r2c1)/n=(6353)/258=12.94E_{21}=(r_2*c_1)/n=(63*53)/258=12.94

E22=(r2c2)/n=(8153)/258=16.64E_{22}=(r_2*c_2)/n=(81*53)/258=16.64

E23=(r2c3)/n=(4653)/258=9.45E_{23}=(r_2*c_3)/n=(46*53)/258=9.45

E24=(r2c4)/n=(2353)/258=4.72E_{24}=(r_2*c_4)/n=(23*53)/258=4.72

E25=(r2c5)/n=(4553)/258=9.24E_{25}=(r_2*c_5)/n=(45*53)/258=9.24


Next is to determine the test statistic given as,

χ2=i=12j=15(OijEij)2/Eij\chi^2_*=\displaystyle\sum^2_{i=1}\displaystyle\sum^5_{j=1}(O_{ij}-E_{ij})^2/E_{ij}

Now,

χ2=(5850.06)2/50.05+(7464.36)2/64.36+(3636.55)2/36.55+(1218.28)2/18.28+(2535.76)2/35.76+(512.94)2/12.94+(716.64)2/16.64+(109.45)2/9.45+(114.72)2/4.72+(209.24)2/9.24=39.4412(4dp)\chi^2_*=(58-50.06)^2/50.05+(74-64.36)^2/64.36+(36-36.55)^2/36.55+(12-18.28)^2/18.28+(25-35.76)^2/35.76+(5-12.94)^2/12.94+(7-16.64)^2/16.64+(10-9.45)^2/9.45+(11-4.72)^2/4.72+(20-9.24)^2/9.24=39.4412(4dp)

χ2\chi^2_* is compared with the table value at α\alpha level of significance with (r1)(c1)=(21)(51)=14=4(r-1)*(c-1)=(2-1)*(5-1)=1*4=4 degrees of freedom.

The table value is χα=0.01,42=13.2767\chi^2_{\alpha=0.01,4}=13.2767 and the null hypothesis is rejected if, χ2>χ0.01,42.\chi^2_*\gt\chi^2_{0.01,4}.


Since χ2=39.4412>χ0.01,42=13.2767,\chi^2_*=39.4412\gt\chi^2_{0.01,4}=13.2767, we reject the null hypothesis and conclude that there is no sufficient evidence to show that the gender of a professor is independent of the department at 1% significance level.


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