Question #276042

The data for a certain test is provided below





X 100 200 300 400 500 600 700




Y 30 50 60 80 100 110 130





Compute the value of the correlation.




Find the equation of the regression lime.


1
Expert's answer
2021-12-06T17:38:32-0500

 correlation:

r=(xix)(yiy)(xix)2(yiy)2=0.9972r=\frac{\sum (x_i-\overline{x})(y_i-\overline{y})}{\sqrt{\sum (x_i-\overline{x})^2\sum(y_i-\overline{y})^2}}=0.9972


regression line:

y=ax+by=ax+b


a=(xix)(yiy)(xix)2=0.1643a=\frac{\sum (x_i-\overline{x})(y_i-\overline{y})}{\sum (x_i-\overline{x})^2}=0.1643


b=yax=14.2857b=\overline{y}-a\overline{x}=14.2857


y=0.1643x+14.2857y=0.1643x+14.2857


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