Find the value of x so that the area under the normal curve between μ and x is approximately 0.4800 and the value of x is greater than μ.
"P(Z<\\dfrac{x-\\mu}{\\sigma})=0.9800"
"\\dfrac{x-\\mu}{\\sigma}\\approx2.053749"
"x\\approx\\mu+2.053749\\sigma"
Given "\\mu=185, \\sigma=18."
"x\\approx221.967"
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