Given the cumulative distribution,
F(x)=1/2(x−1), we can determine the p(1⩽x⩽4.1) as follows.
p(1⩽x⩽4.1)=F(4.1)−F(1)
Now,
F(4.1)=(4.1−1)/2=3.1/2=0.88034084 and F(1)=(1−1)/2=0
Therefore,
p(1⩽x⩽4.1)=F(4.1)−F(1)=0.88034084−0=0.88034084
Thus, pr(1⩽x⩽4.1)=0.8803(4dp)
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