Question #271814

A water bottle company produces bottles with a net volume 400ml each. It is known that the standard deviation of the volume is 12ml. A sample of 50 bottles is tested.


If the sample yields mean volume of 420ml, construct a hypothesis test at the \alpha =0.01 level of significance for the null hypotheses H_(0):\mu =400ml against the alternative hypothesis H_(A):\mu !=400ml. State your conclusion and give a reason for your answer.

1
Expert's answer
2021-11-30T09:32:16-0500

The hypotheses tested are,

H0:μ=400H_0:\mu= 400

AgainstAgainst

HA:μ400H_A:\mu\not=400

We are given the following,

xˉ=420, σ=12, n=50\bar{x}=420,\space \sigma=12,\space n=50

We will apply the standard normal distribution to perform this hypothesis test as follows.

Zc=(xˉμ)/(σ/n)=(420400)/(12/50)=20/1.6971=11.785113Z_c=(\bar{x}-\mu)/(\sigma/\sqrt{n})=(420-400)/(12/\sqrt{50})=20/1.6971=11.785113

ZcZ_c is compared with the standard normal table value at α=0.01\alpha=0.01 given as, Z0.01/2=Z0.005=2.575Z_{0.01/2}=Z_{0.005}=2.575 and the null hypothesis is rejected if Zc>Z0.005.Z_c\gt Z_{0.005}.

Since Zc=11.785113>Z0.005=2.575Z_c=11.785113\gt Z_{0.005}=2.575, we reject the null hypothesis and we conclude that there is no sufficient evidence to show that the average net volume for bottles is 400 ml at 1% level of significance.


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