Question #271597

an agricultural scientist is comparing maize yields per acre for which a nitrate based fertilizer has been used to those from plots having a Sulphur based fertilizer. A sample of 100 acres using nitrate has yielded an average of 56.2 bags per acre with a standard deviation of 12.5 bags. The sample of 150 acres with sulphur fertilizer has yielded an average of 52.6 bags per acre with a standard

deviation of 13.8 bags. Test the relevant hypothesis to validate or invalidate whether

nitrate based fertilizer is superior at 10 percent significance level

1
Expert's answer
2021-11-29T16:52:05-0500

μ1\mu_1 is mean nitrate based fertilizer

μ2\mu_2 is mean Sulphur based fertilizer


H0:μ1=μ2H_0:\mu_1=\mu_2 , nitrate based fertilizer is not superior

Ha:μ1<μ2H_a:\mu_1<\mu_2 , nitrate based fertilizer is superior


t=x1x2s12/n1+s22/n2=56.252.612.52/100+13.82/150=2.139t=\frac{\overline{x}_1-\overline{x}_2}{\sqrt{s^2_1/n_1+s^2_2/n_2}}=\frac{56.2-52.6}{\sqrt{12.5^2/100+13.8^2/150}}=2.139


df=(s12/n1+s22/n2)2(s12/n1)2n11+(s22/n2)2n21=226df=\frac{(s_1^2/n_1+s^2_2/n_2)^2}{\frac{(s_1^2/n_1)^2}{n_1-1}+\frac{(s^2_2/n_2)^2}{n_2-1}}=226


critical value:

tcrit=1.652t_{crit}=-1.652


Since t>tcritt>t_{crit} , we accept the null hypothesis. Nitrate based fertilizer is not superior


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