A labor union spokesman claims that 75% of union members will support a strike if their basic demands are not met. A company spokesman believes the true percentage is higher and runs a hypothesis testing at 10% significance level. (a) Compute the test statistic if 100 of 125 union members say they will strike.
"H_0: p = 0.75 \\\\\n\nH_1: p <0.75 \\\\\n\n\\hat{p} = \\frac{100}{125} = 0.8"
(a) Test-statistic
"Z = \\frac{\\hat{p} \u2013 p}{\\sqrt{\\frac{pq}{n}}} \\\\\n\n= \\frac{0.8-0.75}{\\sqrt{\\frac{0.75 \\times 0.25}{125}}} \\\\\n\n= \\frac{0.05}{0.03873} \\\\\n\n= 1.29"
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