6. A sample of 100 fluorescent tubes from the short life Tube Company gives a mean length of life of 20.5 hours with a standard deviation of 1.6 hours. Find a 95% confidence interval for the average length of life of those tubes
"n=100 \\\\\n\n\\bar{x} = 20.5 \\\\\n\n\\sigma = 1.6 \\\\\n\nME = Z_{\u03b1\/2} \\frac{\\sigma}{\\sqrt{n}} \\\\\n\nME = 1.96 \\times \\frac{1.6}{\\sqrt{100}} = 0.313 \\\\\n\nLower \\; limit = \\bar{x} -ME \\\\\n\n= 20.5 -0.313 = 20.187 \\\\\n\nUpper \\; limit = \\bar{x} + ME \\\\\n\n= 20.5 + 0.313 = 20.813"
Comments
Leave a comment