Question #270914

Find the joint pmf of two independent poissonally distributed random variables X and Y where

μ1 = μx and μ2 = μy. Then evaluate P(X + Y = 5).


1
Expert's answer
2021-11-25T13:38:30-0500

 pmf of X+Y:

f=P(X+Y=K)=(μx+μy)keμxμyk!f=P(X+Y=K)=\frac{(\mu_x+\mu_y)^ke^{-\mu_x-\mu_y}}{k!}


P(X+Y=5)=(μx+μy)5eμxμy5!P(X+Y=5)=\frac{(\mu_x+\mu_y)^5e^{-\mu_x-\mu_y}}{5!}


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