Find the joint pmf of two independent poissonally distributed random variables X and Y where
μ1 = μx and μ2 = μy. Then evaluate P(X + Y = 5).
pmf of X+Y:
f=P(X+Y=K)=(μx+μy)ke−μx−μyk!f=P(X+Y=K)=\frac{(\mu_x+\mu_y)^ke^{-\mu_x-\mu_y}}{k!}f=P(X+Y=K)=k!(μx+μy)ke−μx−μy
P(X+Y=5)=(μx+μy)5e−μx−μy5!P(X+Y=5)=\frac{(\mu_x+\mu_y)^5e^{-\mu_x-\mu_y}}{5!}P(X+Y=5)=5!(μx+μy)5e−μx−μy
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