The linear regression equation for a data set is ˆy = 1.2 − 3.2 x. The actual value is -12.6, when  x = 5. What is the residual value at x=5?
residual =
Given Regression Equation:
"y=1.2-3.2x"
Calculating the Predicted value at x =5 :
"y = 1.2 -3.2 \\times 5 \\\\\n\ny = -14.8"
The Actual Value at x = 5 is given : -12.6
residual = actual – predicted
residual "= -12.6 -(-14.8) = 2.2"
The Required Residual is 2.2
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