Question

The linear regression equation for a data set is ˆy = 1.2 − 3.2 x. The actual value is -12.6, when  x = 5. What is the residual value at x=5?

residual =

Answer 1

Given Regression Equation:

$y=1.2-3.2x$

Calculating the Predicted value at x =5 :

$y = 1.2 -3.2 \times 5 \\ y = -14.8$

The Actual Value at x = 5 is given : -12.6

residual = actual – predicted

residual $= -12.6 -(-14.8) = 2.2$

The Required Residual is 2.2