Question #268233

2. The equation of two regressions obtained in a correlation




analysis of 60 observations are 5π‘₯ = 6𝑦 + 24 and




1000𝑦 = 768π‘₯ βˆ’ 3608. What is the correlation coefficient?




Find the ratio of the coefficient of variability of x to that of y.




What is the ratio of the variations of x and y?

Expert's answer

Regression lines:

x=6y/5+24/5x=6y/5+24/5

y=768x/1000βˆ’3608/1000y=768x/1000-3608/1000


correlation coefficient:

r=axyayx=65β‹…7681000=0.92r=\sqrt{a_{xy}a_{yx}}=\sqrt{\frac{6}{5}\cdot \frac{768}{1000}}=0.92


 ratio of the coefficient of variability of x to that of y:


V(x)V(y)=axyayx=768/10006/5=0.64\frac{V(x)}{V(y)}=\frac{a_{xy}}{a_{yx}}=\frac{768/1000}{6/5}=0.64


ratio of the variations of x and y:

r2=0.922=0.8464r^2=0.92^2=0.8464


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