Question #267799

If X is normally distributed with mean 15 and variance 16, find mean & standard deviation of Y = 3X + 3


1
Expert's answer
2021-11-18T12:23:12-0500

E(Y)=E(3X+3)=3E(X)+3=345+3=138.E(Y)=E(3X+3)=3E(X)+3=3*45+3=138.

Var(Y)=Var(3X+3)=32Var(X)=916=144.Var(Y)=Var(3X+3)=3^2Var(X)=9*16=144.

σ(Y)=Var(Y)=144=12.\sigma(Y)=\sqrt{Var(Y)}=\sqrt{144}=12.


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