If X is normally distributed with mean 15 and variance 16, find mean & standard deviation of Y = 3X + 3
E(Y)=E(3X+3)=3E(X)+3=3∗45+3=138.E(Y)=E(3X+3)=3E(X)+3=3*45+3=138.E(Y)=E(3X+3)=3E(X)+3=3∗45+3=138.
Var(Y)=Var(3X+3)=32Var(X)=9∗16=144.Var(Y)=Var(3X+3)=3^2Var(X)=9*16=144.Var(Y)=Var(3X+3)=32Var(X)=9∗16=144.
σ(Y)=Var(Y)=144=12.\sigma(Y)=\sqrt{Var(Y)}=\sqrt{144}=12.σ(Y)=Var(Y)=144=12.
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