Answer to Question #267347 in Statistics and Probability for Dawnnn

Question

emotional quotient (EQ) score on the least version of Sirug EQ Test are transformed so as follow a normal distribution with a mean of 110 and standard deviation of 15. find the 96th percentile of the distribution of Emotional Quotient

Answer 1

$x=\mu+Z\sigma$

Firstly needs to determine Z value using normal distribution table and 0.96;

$x=110+1.75\times15$

$x=110+26.25=136.25$

The means 96th percentile of the distribution of Emotional Quotient is 136.25.