Question #266779

What is the pero probability that ramdomly selected year will have precipitation greater than 18 inches for the first 7 months?

1
Expert's answer
2021-11-17T03:47:59-0500

Let XX be a random variable representing the precipitation for the first 7 months of a year. XX follows a normal distribution with mean μ=19.32\mu=19.32 and standard deviation σ=2.44\sigma=2.44. We need to find the probability,

p(X>18)=p((Xμ)/σ>(18μ)/σ)=p(Z>(1819.32)/2.44)=p(Z>0.5409836)p(X\gt 18)=p((X-\mu)/\sigma\gt (18-\mu)/\sigma)=p(Z\gt (18-19.32)/2.44)=p(Z\gt -0.5409836)

This probability can be written as,

p(Z>0.5409836)=1p(Z<0.5409836)=10.2946=0.7054p(Z\gt -0.5409836)=1-p(Z\lt -0.5409836)=1-0.2946=0.7054

Therefore, the  probability that a randomly selected year will have precipitation greater than 18 inches for the first 7 months is 0.7054.


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