Question #266339

Rolling a dice three times, evaluate the probability of having at least one 6. (5 marks)


Drawn a card from a deck of 52 cards, verify whether the following events are statistically independent:


a) A = {drawing of a picture card}; B ={drawing of a hearth card}



b) What if the king of hearths is missing from the deck of cards?



c) What if a card, at random, is missing? (5 marks)



d) if a card is drawn at random from a deck of cards. Find the probability of getting the King of hearts.



1
Expert's answer
2021-11-16T13:28:19-0500

1.


P(at least one 6)=1(56)3=91216P(at \ least\ one\ 6)=1-(\dfrac{5}{6})^3=\dfrac{91}{216}

2.

a)

P(A)=1252=313P(A)=\dfrac{12}{52}=\dfrac{3}{13}

P(B)=1352=14P(B)=\dfrac{13}{52}=\dfrac{1}{4}

P(AB)=352P(A\cap B)=\dfrac{3}{52}

P(A)P(B)=313(14)=352=P(AB)P(A)P(B)=\dfrac{3}{13}(\dfrac{1}{4})=\dfrac{3}{52}=P(A\cap B)

The events AA and BB are statistically independent.


b)


P(A)=1151P(A)=\dfrac{11}{51}

P(B)=1251=417P(B)=\dfrac{12}{51}=\dfrac{4}{17}

P(AB)=351=117P(A\cap B)=\dfrac{3}{51}=\dfrac{1}{17}

P(A)P(B)=1151(417)=44867117=P(AB)P(A)P(B)=\dfrac{11}{51}(\dfrac{4}{17})=\dfrac{44}{867}\not=\dfrac{1}{17}=P(A\cap B)

The events AA and BB are not statistically independent.


c)

i) The missing card is neither heart nor picture.


P(A)=1251=417P(A)=\dfrac{12}{51}=\dfrac{4}{17}

P(B)=1351P(B)=\dfrac{13}{51}

P(AB)=451P(A\cap B)=\dfrac{4}{51}

P(A)P(B)=417(1351)=52867451=P(AB)P(A)P(B)=\dfrac{4}{17}(\dfrac{13}{51})=\dfrac{52}{867}\not=\dfrac{4}{51}=P(A\cap B)

The events AA and BB are not statistically independent.


ii) The missing card is picture but is not heart


P(A)=1151P(A)=\dfrac{11}{51}

P(B)=1351P(B)=\dfrac{13}{51}

P(AB)=451P(A\cap B)=\dfrac{4}{51}

P(A)P(B)=1151(1351)=1432601451=P(AB)P(A)P(B)=\dfrac{11}{51}(\dfrac{13}{51})=\dfrac{143}{2601}\not=\dfrac{4}{51}=P(A\cap B)

The events AA and BB are not statistically independent.


iii) The missing card is heart but is not picture


P(A)=1251=417P(A)=\dfrac{12}{51}=\dfrac{4}{17}

P(B)=1251=417P(B)=\dfrac{12}{51}=\dfrac{4}{17}

P(AB)=451P(A\cap B)=\dfrac{4}{51}

P(A)P(B)=417(417)=16289451=P(AB)P(A)P(B)=\dfrac{4}{17}(\dfrac{4}{17})=\dfrac{16}{289}\not=\dfrac{4}{51}=P(A\cap B)

The events AA and BB are not statistically independent.


iv) The missing card is heart and is picture


P(A)=1151P(A)=\dfrac{11}{51}

P(B)=1251=417P(B)=\dfrac{12}{51}=\dfrac{4}{17}

P(AB)=351=117P(A\cap B)=\dfrac{3}{51}=\dfrac{1}{17}

P(A)P(B)=1151(417)=44867117=P(AB)P(A)P(B)=\dfrac{11}{51}(\dfrac{4}{17})=\dfrac{44}{867}\not=\dfrac{1}{17}=P(A\cap B)

The events AA and BB are not statistically independent.


d)


P(King of hearts)=152P(King\ of\ hearts)=\dfrac{1}{52}


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