A random variable X has the following probability function : x: -2 -1 0 1 2 3 f(x): 0*1 k 0*1 2 2k 0*3 3k (i) Determine the distribution function F(x) of X.
Solution:
The sum of probabilities in a probability distribution is 1.
So, 0.1+k+0.2+2k+0.3+k=10.1+k+0.2+2k+0.3+k=10.1+k+0.2+2k+0.3+k=1
⇒4k+0.6=1⇒4k=0.4⇒k=0.44⇒k=0.1\Rightarrow 4k+0.6=1 \\\Rightarrow 4k=0.4 \\\Rightarrow k=\dfrac{0.4}4 \\\Rightarrow k=0.1⇒4k+0.6=1⇒4k=0.4⇒k=40.4⇒k=0.1
Thus, probability distribution is:
x=−2,f(x)=0.1x=−1,f(x)=0.1x=0,f(x)=0.2x=1,f(x)=0.2x=2,f(x)=0.3x=3,f(x)=0.1x=-2, f(x)=0.1 \\x=-1, f(x)=0.1 \\x=0,f(x)=0.2 \\x=1,f(x)=0.2 \\x=2,f(x)=0.3 \\x=3,f(x)=0.1x=−2,f(x)=0.1x=−1,f(x)=0.1x=0,f(x)=0.2x=1,f(x)=0.2x=2,f(x)=0.3x=3,f(x)=0.1
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments