The age of individual students have normal distribution with mean 18.6 and standard deviation 1.24. At Buting Senior High School, there 76 students from HUMSS A and HUMSS B with the same distribution as the entire age of grade 11.
What is the sample variance?
Here, "\\mu=18.6, \\space \\sigma=1.24, \\space n=76"
Since the ages of 76 students from HUMSS A and HUMSS B has the same distribution as the entire age of grade 11 then, the sample standard deviation given by "\\sigma_{\\bar{x}}" is,
"\\sigma _{\\bar{x}}=\\sigma\/\\sqrt n=1.24\/\\sqrt{76}= 0.1422378"
The sample variance is given as,
"\\sigma^2_{\\bar{x}}=(\\sigma_{\\bar{x}})^2=0.1422378^2= 0.02023158"
Therefore, the sample variance is 0.02023158.
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